5y/6y+3y/3y^3

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Solution for 5y/6y+3y/3y^3 equation: 


y in (-oo:+oo)

((3*y)/3)*y^3+((5*y)/6)*y = 0

y^4+5/6*y^2 = 0

t_1 = y^2

1*t_1^2+5/6*t_1^1 = 0

t_1^2+5/6*t_1 = 0

DELTA = (5/6)^2-(0*1*4)

DELTA = 25/36

DELTA > 0

t_1 = ((25/36)^(1/2)-5/6)/(1*2) or t_1 = (-(25/36)^(1/2)-5/6)/(1*2)

t_1 = 0 or t_1 = -5/6

t_1 = -5/6

y^2+5/6 = 0

1*y^2 = -5/6 // : 1

y^2 = -5/6

t_1 = 0

y^2+0 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y = 0

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